To To Seeing a post by the boss yesterday, I decided to follow the trend and promote a wave of our py encryption technology. The attached compressed package contains a pyc file. The correct input is a private key corresponding to the Ethereum address 0xd0fe5288c5320bb898498fa45fa4f7c324e1e074. The balance in the address is 5ETH (current value 12,300 yuan). You can check the balance of the address at this link (if before the end time) Being transferred means that a boss has completed the game) https://etherscan.io/address/0xd0fe5288c5320bb898498fa45fa4f7c324e1e074 <br>
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Netizens reply: To To Front row, see how big guys crack I bet that no one can break 50 cents
Netizens reply: To To Can play, commercial encryption is not easy to break Although I can't reverse it at all
Netizens reply: To To What's the use of pyc encryption? . . Is it not good to directly pyinstaller binary
Netizen reply: To To More and more ridiculous, I recompile a python, and then modify the pyc encoding format generated by python, you let me guess? ? That's not a mistake
Netizen reply: To To Quote: nny published on 2020-9-1112:57 More and more ridiculous, I recompile a python, and then modify the pyc encoding format generated by python, you let me guess? ? That's right...
Netizen Reply: To To The correct input is a private key corresponding to the Ethereum address of 0xd0fe5288c5320bb898498fa45fa4f7c324e1e074 This is not the same thing as BIP39 Enter the content correctly (words within 12 ranges) to get the private key Does this still use decryption? How about you first prove that the private key has nothing to do with the input content? If you really want to prove that PYC encryption can’t be decrypted, you might as well make a crackme and send it to a place like my love
Netizen reply: To To Quote: jq8778 published on 2020-9-1113:31 The correct input is a private key corresponding to the Ethereum address of 0xd0fe5288c5320bb898498fa45fa4f7c324e1e074 This is not the same as BIP39...
Netizens reply: To To Quote: Xixing Temple You Youzi Published on 2020-9-11 13:32 Not a mnemonic word, but a traditional private key with a combination of 64 letters and numbers
Netizens reply: To To Quote: jq8778 published on 2020-9-1113:36 You need to prove first that the private key has nothing to do with the input content
Netizen reply: To To PyProtect2.0 https://pyprotect.angelic47.com It should be the AVM virtual machine created by the author Give up, wait for someone to take the hand to reverse
Netizens reply: To To Quote: nekolate published on 2020-9-1114:03 PyProtect2.0 https://pyprotect.angelic47.com/

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